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Posted: October 14th, 2022
30.0 mL of a 1.00 M Fe(NO3)2 solution was reacted with 25.0
30.0 mL of a 1.00 M Fe(NO3)2 solution was reacted with 25.0 mL of a 0.600 M solution of K3PO4 to produce the solid Fe3(PO4)2 by the balanced equation.What is the limiting reagent? How many grams of Fe3(PO4)2 will be produced?2. If 50 mL of a 1.00 M solution of CaCl2 solution A is diluted to 100. mL solution B and 70 mL of solution B is mixed with 45 mL of a 2.00 M solution of CaCl2 solution c to produce solution D, what is the molarity of the final solution (solution D)3. Neutralization reaction equation, determine the volume of a 0.150 M H3PO4 solution needed to neutralize 27.0 mL of a 0.300 M Mg(OH)2 solution. Determine the grams of Mg3(PO4)2 that will be produced by neutralization reaction. Balanced equation 2H3PO4(aq)+3 Mg(OH)2(aq)>Mg3(PO4)2(s)+6H20(l)4. Balanced molecular equation, complete ionic equation, and net ionic equationNa3PO4(aq)+Zn(NO3)2(aq)>NaNO3(aq)+Zn3(PO4)2(s)5. equilibrium constantCO(g)+H2O(g)<>CO2(g)+H2(g)2NH3(g)<>3H2(g)+N2(g)
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